Re: [ferret_users] apply an offset on the time axis of a variable

[Ansley Manke - NOAA Federal <ansley.b.manke@xxxxxxxx>]

Yes, that would be a simpler solution, using the same times and referencing them to a different origin.

   yes? let tt = t[gt=`var,return=taxis`]

   yes? define axis/t/t0="..."/units="`var,return=tunits` `var,return=taxis` = tt

with the new date.  In fact, you could just

   yes? set axis/t0="..."  `var,return=taxis`

to change the time origin.  Check the new definition , listing some dates

   yes? show axis/t/L=1:10

On Wed, Apr 26, 2017 at 9:24 PM, Ryo Furue <furue@xxxxxxxxxx> wrote:

Hi Ansley,

yes? let tt = t[gt=`var,return=taxis`]

yes? let tt_plus_50 = ...

yes? define axis/t/t0="`var,return=t0`"/units="`var,return=tunits` `var,return=taxis` = tt_plus_50

Instead of shifting the time axis like this, is it possible to shift just t0  by minus 50 years?

Cheers,

Ryo