Re: time dimension problem

[Jonathan Callahan <callahan@xxxxxxxxxxxxx>]

Zhangfan,

I finally found time to work on your problem.  I've posted an
explanation and a solution in the FAQ pages:

http://ferret.wrc.noaa.gov/Ferret/LAS/FAQ/yearly_averages.htm

Let me know if you have further questions.


-- Jon


Zhangfan Xing wrote:
> 
> Hi, Jon and friends,
> 
> I am having problem to get LAS work properly with
> a netcdf file that represents yearly averages. LAS says:
> 
> You specified a time or depth value that is outside the region contained
> by this dataset.
> 
> I searched mail archive, found an old thread and followed suggestions
> there, but still got same error. The URL of this old thread is
> http://ferret.wrc.noaa.gov/Ferret/LAS/Mail_Archives/fu_2000/msg00032.html
> 
> Attched are relevant parts of my xml file and dump of my netcdf for time.
> 
> Thanks in advance.
> 
> Zhangfan
> 
> --------------------relevant parts of my xml file---------------------
> 
>       <jpl_time_mean units="foo" type="t">
>        <arange start="1980" step="1" size="1"/>
>       </jpl_time_mean >
> 
> --------------------dump of my netcdf for time------------------------
> 
> [xing@foo try]$ ncdump -v time Vave.y1980.cdf | more
> netcdf Vave.y1980 {
> dimensions:
>         time = UNLIMITED ; // (1 currently)
>         depth = 46 ;
>         lat = 224 ;
>         lon = 360 ;
> variables:
>         float lat(lat) ;
>                 lat:long_name = "Latitude" ;
>                 lat:units = "degrees_north" ;
>                 lat:actual_range = -90.f, 90.f ;
>         float lon(lon) ;
>                 lon:long_name = "Longitude" ;
>                 lon:units = "degrees_east" ;
>                 lon:actual_range = 0.f, 360.f ;
>         float depth(depth) ;
>                 depth:long_name = "depth" ;
>                 depth:units = "meters" ;
>                 depth:positive = "down" ;
>                 depth:actual_range = 0.f, 6000.f ;
>         float time(time) ;
>                 time:long_name = "Time in years" ;
>                 time:units = "years" ;
>         float Vave(time, depth, lat, lon) ;
>                 Vave:units = "M/S" ;
>                 Vave:long_name = "Meridional Velocity" ;
>                 Vave:missing_value = -1.e+10f ;
>                 Vave:add_offset = 0.f ;
>                 Vave:scale_factor = 1.f ;
> 
> // global attributes:
>                 :title = "Annual Mean 1980" ;
>                 :history = "Converted from MITGCM output\n",
>     "" ;
> data:
> 
>  time = 1980 ;
> }
>