Hi
You can define any time axis that you want to. Look at DEFINE
AXIS, especially the qualifiers: /UNITS, /T0, and /EDGES
http://ferret.pmel.noaa.gov/Ferret/documentation/users-guide/commands-reference/DEFINE#PartII-Define_Axis
If the axis has time units, such as Days or Months, and a time
origin defined with /T0, then Ferret will treat it as a calendar
axis. This means it will be able to translate time automatically
between this axis and other time axes, and will label plot axes
with time units. Special calendar axes that are a year long or
less and are defined with a /MODULO qualifier will let you do
modulo operations such as calculating an annual cycle.
It sounds like you have already computed some monthly data and
just want to define a time axis that shows the right dates for it.
Take a look at this example. You will need to change it for your
case. This is an equally spaced axis.
yes? DEFINE AXIS/T0=1-JAN-0000/T=0:12:1/EDGES/units=months
all_months
yes? show axis/t all_months
name axis # pts
start end
ALL_MONTHS TIME 12 r 16-JAN-0000
05:14 16-DEC-0000 00:34
T0 = 1-JAN-0000
Axis span (to cell edges) = 12
L T TBOX
TBOXLO TSTEP (MONTHS)
1> 16-JAN-0000 05:14:33 1
01-JAN-0000 00:00:00 0.5
2> 15-FEB-0000 15:43:39 1
31-JAN-0000 10:29:06 1.5
3> 17-MAR-0000 02:12:45 1
01-MAR-0000 20:58:12 2.5
4> 16-APR-0000 12:41:51 1
01-APR-0000 07:27:18 3.5
5> 16-MAY-0000 23:10:57 1
01-MAY-0000 17:56:24 4.5
6> 16-JUN-0000 09:40:03 1
01-JUN-0000 04:25:30 5.5
7> 16-JUL-0000 20:09:09 1
01-JUL-0000 14:54:36 6.5
8> 16-AUG-0000 06:38:15 1
01-AUG-0000 01:23:42 7.5
9> 15-SEP-0000 17:07:21 1
31-AUG-0000 11:52:48 8.5
10> 16-OCT-0000 03:36:27 1
30-SEP-0000 22:21:54 9.5
11> 15-NOV-0000 14:05:33 1
31-OCT-0000 08:51:00 10.5
12> 16-DEC-0000 00:34:39 1
30-NOV-0000 19:20:06 11.5
I don't know what kind of axis you have your computed 10 months
of data on. Say they're just listed on an axis, L=1:10. It
doesn't matter what the time axis is for your data, as long as it
represents months starting with the first of your 10 months.
yes? list/x=300/y=20 my_data
...
1 / 1: 25.94
2 / 2: 25.60
3 / 3: 25.58
4 / 4: 25.97
5 / 5: 26.76
6 / 6: 27.39
7 / 7: 27.78
8 / 8: 28.26
9 / 9: 28.35
10 / 10: 28.32
Now what if, for example, your 10 months run from May through
February. You could make this definition:
yes? DEFINE AXIS/T0=1-may-0000/T=0:10:1/EDGES/units=months
ten_months
*** NOTE: /UNIT=MONTHS is ambiguous ...
using 1/12 of 365.2425 days
yes? show axis/t ten_months
name axis # pts start end
TEN_MONTHS TIME 10mr 16-MAY 05:14
14-FEB 03:36
T0 = 1-MAY-0000
Axis span (to cell edges) = 10 (modulo length = 12)
L T TBOX
TBOXLO TSTEP (MONTHS)
1> 16-MAY 05:14:33 1 01-MAY
00:00:00 0.5
2> 15-JUN 15:43:39 1 31-MAY
10:29:06 1.5
3> 16-JUL 02:12:45 1 30-JUN
20:58:12 2.5
4> 15-AUG 12:41:51 1 31-JUL
07:27:18 3.5
5> 14-SEP 23:10:57 1 30-AUG
17:56:24 4.5
6> 15-OCT 09:40:03 1 30-SEP
04:25:30 5.5
7> 14-NOV 20:09:09 1 30-OCT
14:54:36 6.5
8> 15-DEC 06:38:15 1 30-NOV
01:23:42 7.5
9> 14-JAN 17:07:21 1 30-DEC
11:52:48 8.5
10> 14-FEB 03:36:27 1 29-JAN
22:21:54 9.5
Specifying year 0000 will cause Ferret to not show any year on
plots. If the data does correspond to time in some year, then give
the starting year in the time origin of your axis definition.
Then put your data onto this axis, with this:
yes? let my_data_months = my_data[gt=ten_months@asn]
yes? plot/x=300/y=20 my_data_months
On 10/31/2016 11:53 AM, afwande juliet
wrote:
Dear All
I have some monthly data only 10months for one year. I do areal
average over a box using cdo, then I use ferret to plot semi
annual cycle , I.e I know ferret needs 12 data points for
annual cycle but for me I have only 10months of data that I need
to plot. Does someone have an idea