Re: Locate good data point

[Jonathan Callahan <callahan@xxxxxxxxxxxxx>]

Jens-Olaf,

There's nothing specific to do this but you can reverse the data with
something like this:

! Assuming your data has 120 points in X
let reverse_i = 121 - i[gx=temp]
let reverse_temp = samplei(temp,reverse_i)

You could reverse your data and then proceed as before or you can get
the indices, reverse them and then compress again.  The left most
indices will now refer to the easternmost valid data points.

But Andrew's solution looks cleaner than mine.


-- Jon

Jens-Olaf Beismann wrote:
> 
> Jonathan,
> 
> > yes? show func compressi
> > COMPRESSI(DAT)
> >     Returns data, compressed along the I axis: Missing points moved to
> > the end
> >     DAT: variable to compress in I
> 
> great! Thanks a lot.
> 
> I should have been more precise in my first  question to avoid bothering
> you again, but is there also a function that does it the other way
> around? I.e., how do I find the index of the easternmost point? In the
> way Andrew Wittenberg proposed?
> 
> Best regards,
> 
> Jens-Olaf
> _____________________________________________________
>  Jens-Olaf Beismann
>  IfM Kiel - FB 1
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