# Re: mixed depth layer using no standard level data

```Dear Dr, Ansley Manke

Thank you for your valuable help.

I have an error in definnig the axis
"define axis/z depax=dep" like below
**errors command syntax: illegul name:depax=dep

Could you tell me how can solve this problem ?

>file/skip=1/var="tem,sal,dep" sample.dat
>define axis/z depax=dep
>define grid/z=depax depthgrid
>
>! reread the data using the grid.
>
>file/skip=1/var="tem,sal,dep"/g=depthgrid sample.dat
>
>let rho=rho_un(sal,tem,dep)
>let diffr=rho-rho[k=1]-0.3    ! <-- note now k
>let mldr=diffr[z=@loc:0]      ! <-- note now z
>list mldr
>
>Ansley Manke
>
>Namba Takaya wrote:
>
> > Dear sir.
> >
> > I want to calculate the mixed layer depth from the data (file name
> > sample.txt) below.
> >
> > The data have randam depth (not the standard depth).
> >
> > temperature      salinity      depth
> > 27.96            33.5          4.1
> > 27.88            33.5          10.9
> > 27.84            33.7          20.4
> > 27.78            33.8          29.4
> > 27.66            33.9          42.5
> > 27.60            34.2          50.2
> > 27.31            34.6          59.8
> > 27.35            34.6          70.4
> > 27.36            34.5          77.3
> >
> > I want to define the mixed layer depth by density difference from the
> > surface.
> > If I define the mixlayer depth, 0.3 different in density from the
surface,
> > how I can calculate the mix layer depth?
> >
> > What I did is below
> >
> > file /var="tem,sal,dep: sample.txt
> > let ryo=ryo_un(sal,tem,dep)
> > let diffr=ryo-ryo[i=1]-0.3
> > let mldr=diffr[dep=@loc:0]   !!! this is problem.
> > list mldr
> >
> > but I could not make it.
> >
> > Could you tell me why or could you tell me some other ways to do it?
> >
> > Takaya Namba
> >
> >
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>

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