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Re: [ferret_users] define grid
Hi David,
It looks to me as if what you may want is a SET REGION command, rather
than DEFINE GRID:
let imax = `raz[d=1],return=iend`
let jmax = `raz[d=1],return=jend`
set region/I=2:`imax-1`/J=2:`jmax-1`
You can also use DEFINE REGION to give your region a name, and use that
name to store a particular region setting.
To use DEFINE GRID, you need axis names, not index ranges. So the
following would keep the Z and T axis of the grid of your variable, and
create new axes using the same units and coordinates as the original
axis for the variable.
let imax = `raz[d=1],return=iend`
let jmax = `raz[d=1],return=jend`
define axis/x/units=`raz[d=1],return=xunits` newxax =
x[gx=raz[d=1],i=2:`imax-1`]
define axis/y/units=`raz[d=1],return=yunits` newyax =
y[gx=raz[d=1],j=2:`jmax-1`]
define grid/like=raz[d=1]/x=newxax/y=newyax newgrid
Ansley
David Wang wrote:
Hello Ferreters,
I'm intending to use a subset of an existing grid to define a new
grid, onto which another variable will be regridded by the
transformation @ASN. I tried something like:
let imax = `raz[d=1],return=iend`
let jmax = `raz[d=1],return=jend`
define grid/like=raz[d=1]/I=2:`imax-1`/J=2:`jmax-1` newgrid
but it didn't go through, and told me:
**ERROR: unknown command qualifier: I=2:`imax-1`
Any hints?
Thanks,
- David
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